Solving Linear Equations and Operations

The video tutorial explains how to solve one-step equations by isolating the variable using inverse operations. It covers two examples: x + 17 = -32 and x - 24 = -59. For each equation, the tutorial demonstrates the steps to isolate the variable, solve the equation, and verify the solution by substitution. The process involves performing the opposite operation on both sides of the equation to maintain equality and checking the solution to ensure it satisfies the original equation.

What is the first step in solving the equation x + 17 = -32?

• Divide both sides by 17

• Multiply both sides by 17

• Subtract 17 from both sides

• Add 17 to both sides

Tags

CCSS.6.EE.B.7

What operation is used to isolate x in the equation x + 17 = -32?

• Division

• Subtraction

• Addition

• Multiplication

Tags

CCSS.6.EE.B.7

What is the solution to the equation x + 17 = -32?

• x = -15

• x = 15

• x = -49

• x = 49

Tags

CCSS.6.EE.B.5

How do you verify the solution to the equation x + 17 = -32?

• By multiplying -32 by 17

• By adding 17 to -32

• By checking if x = 0

• By substituting x = -49 into the equation

Tags

CCSS.6.EE.B.7

What is the second equation discussed in the video?

• x + 24 = -59

• x - 24 = 59

• x - 24 = -59

• x + 24 = 59

Tags

CCSS.6.EE.B.7

What operation is used to solve the equation x - 24 = -59?

• Multiply both sides by 24

• Add 24 to both sides

• Subtract 24 from both sides

• Divide both sides by 24

Tags

CCSS.HSA.REI.A.1

What is the inverse operation of subtraction used in the second equation?

• Subtraction

• Addition

• Division

• Multiplication

Tags

CCSS.6.EE.B.7

What is the solution to the equation x - 24 = -59?

• x = -35

• x = 35

• x = 83

• x = -83

Tags

CCSS.6.EE.B.5

How do you verify the solution to the equation x - 24 = -59?

• By adding 24 to -59

• By multiplying -59 by 24

• By substituting x = -35 into the equation

• By checking if x = 0

Tags

CCSS.7.EE.B.4A

What is the purpose of performing inverse operations in solving equations?

• To make the equation more complex

• To change the equation's solution

• To isolate the variable

• To eliminate the variable

Tags

CCSS.7.EE.B.4A