Solving Equations and Fractions

The video tutorial explains how to solve the equation 2x - 6 = 1 by isolating the variable x. It introduces the concept of two-step equations, where subtraction and multiplication are undone to find the solution. The tutorial demonstrates converting the solution from a fraction to a decimal and emphasizes the importance of not rounding for exact solutions. Finally, it verifies the solution by substituting it back into the original equation.

What is the main goal when solving the equation 2x - 6 = 1?

• To simplify the equation to 0

• To find the value of x that makes the equation false

• To determine the value of y

• To find the value of x that makes the equation true

Tags

CCSS.7.EE.B.4A

What is the first step in solving a two-step equation?

• Divide both sides by 2

• Multiply both sides by 2

• Undo the subtraction or addition

• Undo the multiplication

Tags

CCSS.HSA.REI.A.1

What operation is performed to both sides of the equation to undo the subtraction of 6?

• Subtract 6

• Multiply by 6

• Add 6

• Divide by 6

Tags

CCSS.6.EE.B.7

After adding 6 to both sides, what does the equation become?

• x = 1

• x = 7

• 2x = 7

• 2x = 1

Tags

CCSS.7.EE.B.4A

What is the second step in solving the equation after undoing the subtraction?

• Subtract 2 from both sides

• Divide both sides by 2

• Multiply both sides by 2

• Add 2 to both sides

Tags

CCSS.6.EE.B.7

What is the value of x after dividing both sides by 2?

• x = 3.5

• x = 7

• x = 1

• x = 2

Tags

CCSS.7.EE.B.4A

What is the fraction form of the solution for x?

• 7/2

• 3/2

• 5/2

• 1/2

Tags

CCSS.7.NS.A.2D

CCSS.8.NS.A.1

How can the fraction 7/2 be expressed as a decimal?

• 2.0

• 2.5

• 3.5

• 3.0

Tags

CCSS.7.NS.A.2D

CCSS.8.NS.A.1

Why should we not round the decimal when converting from a fraction?

• It makes the solution more complex

• It does not provide the exact solution

• It is easier to work with fractions

• It is not allowed in mathematics

Tags

CCSS.8.EE.C.7B

What is the purpose of substituting the solution back into the original equation?

• To check for errors in calculation

• To find a new solution

• To verify the solution is correct

• To simplify the equation further

Tags

CCSS.8.EE.C.7B