Understanding Division with Remainders

The video tutorial explains how to solve a division problem with a remainder by first solving a simpler equation without a remainder. It demonstrates the use of multiplication to find the dividend and verifies the solution using different methods, including long division. The tutorial also covers solving the equation without a remainder, reinforcing the understanding of division and multiplication relationships.

What is the main problem discussed in the video?

• Solving a multiplication problem

• Finding the dividend when given a quotient and remainder

• Finding the quotient of a division

• Understanding subtraction

Tags

CCSS.3.OA.A.4

What is the simpler equation used to help solve the main problem?

• d divided by 4 equals 15

• d divided by 4 equals 10

• d divided by 4 equals 12

• d divided by 4 equals 8

Tags

CCSS.3.OA.C.7

How is the corresponding multiplication problem related to the division problem?

• It is the inverse operation

• It helps to find the remainder

• It is unrelated

• It complicates the problem

Tags

CCSS.5.OA.B.3

What is the value of 'd' when there is a remainder of three?

• 50

• 45

• 51

• 48

Tags

CCSS.5.NBT.B.6

CCSS.6.NS.B.2

How can you verify the solution to the division problem?

• By dividing the remainder by the quotient

• By multiplying the quotient by the divisor and adding the remainder

• By adding the quotient and remainder

• By subtracting the remainder from the dividend

Tags

CCSS.3.OA.C.7

What is the result of twelve times four?

• 44

• 46

• 48

• 50

Tags

CCSS.4.NBT.B.6

What is the remainder when 51 is divided by 4?

• 3

• 2

• 1

• 4

Tags

CCSS.4.NBT.B.6

What operation is used to check the division problem?

• Multiplication

• Long Division

• Subtraction

• Addition

Tags

CCSS.4.NBT.B.6

What is the dividend 'd' when there is no remainder?

• 50

• 49

• 48

• 47

Tags

CCSS.5.NBT.B.6

CCSS.6.NS.B.2

What is the purpose of solving the equation without a remainder?

• To simplify the understanding

• To complicate the problem

• To change the divisor

• To find a different quotient

Tags

CCSS.5.NBT.B.6

CCSS.6.NS.B.2