Understanding Linear Functions in Tuition Costs

The video tutorial explains how to determine a linear equation representing the cost of tuition as a function of the number of years since 1995. It starts by discussing tuition costs in 1995 and 2005, then introduces function notation and ordered pairs. The tutorial guides viewers through calculating the linear function, determining the slope and intercept, and finalizing the linear equation.

What was the cost of tuition per credit hour in 1995?

• $144

• $238

• $100

• $200

In which year did the tuition cost rise to $238 per credit hour?

• 1995

• 2000

• 2010

• 2005

Tags

CCSS.HSF.LE.B.5

What does the first value in an ordered pair represent in this context?

• Total tuition cost

• Number of years since 1995

• Year

• Cost per credit hour

Tags

CCSS.6.EE.A.2C

How do you calculate the number of years since 1995 for the year 2005?

• Multiply 1995 by 10

• Subtract 1995 from 2005

• Add 10 to 1995

• Divide 2005 by 1995

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

What is the formula for a linear function in slope-intercept form?

• F(x) = mx - b

• F(x) = mx + b

• F(x) = b - mx

• F(x) = x + b

Tags

CCSS.8.EE.B.5

What is the slope of the linear function representing the tuition cost?

• 9.4

• 10

• 94

• 144

Tags

CCSS.8.EE.B.5

What does the y-intercept represent in this context?

• The average cost

• The total increase in cost

• The initial cost in 1995

• The cost in 2005

Tags

CCSS.8.F.B.4

CCSS.HSF.LE.A.2

What is the final linear equation for the tuition cost as a function of years since 1995?

• C(x) = 10x + 238

• C(x) = 238x + 10

• C(x) = 144x + 9.4

• C(x) = 9.4x + 144

Tags

CCSS.HSF-LE.A.1B

How do you determine the change in cost per credit hour?

• Divide 238 by 144

• Multiply 144 by 238

• Add 144 to 238

• Subtract 144 from 238

Tags

CCSS.HSF-LE.A.1B

What is the constant rate of change in the tuition cost?

• 9.4

• 10

• 94

• 144

Tags

CCSS.HSF-LE.A.1B