Differential Equations and Direction Fields

Differential Equations and Direction Fields

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

CCSS
8.EE.C.8B

Standards-aligned

Created by

Lucas Foster

FREE Resource

Standards-aligned

CCSS.8.EE.C.8B
The video tutorial explains how to solve a separable differential equation with an initial condition. It begins by rewriting the equation in a separable form, then integrates both sides to find a general solution. The tutorial continues by solving for y and finding a particular solution using the given initial condition. Finally, the solution is graphed over a direction field to verify its accuracy.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial condition given in the problem?

y(0) = 1

y(3) = 4

y(2) = 3

y(1) = 2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the goal when dealing with a separable differential equation?

To write it in the form of a function of y times dy equals a function of x times dx

To integrate both sides without separating

To find the derivative of x

To solve for x directly

Tags

CCSS.8.EE.C.8B

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you simplify the right side of the equation after separating variables?

By adding a constant

By simplifying fractions

By multiplying by x

By dividing by y

Tags

CCSS.8.EE.C.8B

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the antiderivative of 9/x with respect to x?

9x

9/x^2

9 ln|x|

9x^2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What operation is performed to solve for y after integrating?

Subtracting a constant

Raising to the power of 1/3

Multiplying by a constant

Taking the square root

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of C found using the initial condition?

40

-40

48

-48

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the particular solution of the differential equation?

y(x) = (27 ln x - 48x - 40)^(1/3)

y(x) = (27 ln x - 48x + 40)^(1/3)

y(x) = (27 ln x + 48x - 40)^(1/3)

y(x) = (27 ln x + 48x + 40)^(1/3)

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