Mass of Wire and Line Integrals

Mass of Wire and Line Integrals

Assessment

Interactive Video

Mathematics, Physics

11th Grade - University

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to calculate the total mass of a wire spring with three turns using a density function. It introduces the concept of line integrals and demonstrates how to use parametric equations to simplify the integrand function. The tutorial also covers calculating the magnitude of the derivative and setting up the integration process. Finally, it evaluates the line integral to determine the mass of the wire, providing both an exact value and a decimal approximation.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary goal of the problem discussed in the video?

To measure the density of the wire spring

To find the length of the wire spring

To determine the total mass of the wire spring

To calculate the volume of the wire spring

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What mathematical tool is used to find the mass of the wire?

Double integral

Surface integral

Line integral

Volume integral

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for the function f(r(t)) in this problem?

t^2 + 4t

4 + t^2

4 + t

t^2 + 4

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the magnitude of r'(t) in this calculation?

Square root of 6

Square root of 5

Square root of 4

Square root of 3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many radians correspond to three turns of the wire?

0 to 6π

0 to 4π

0 to 8π

0 to 2π

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the integral expression used to find the mass of the wire?

Integral of (4t + t^3) * sqrt(5) dt

Integral of (4 + t^2) * sqrt(5) dt

Integral of (4t + t^3) dt

Integral of (4 + t^2) dt

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the exact value of the line integral for the mass of the wire?

24 sqrt(5) π (1 + 3π^2)

24 sqrt(5) π (1 + 2π^2)

24 sqrt(5) π (1 + 4π^2)

24 sqrt(5) π (1 + 5π^2)

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