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Understanding Average Cost and Horizontal Asymptotes

Understanding Average Cost and Horizontal Asymptotes

Assessment

Interactive Video

Mathematics, Business

9th - 12th Grade

Practice Problem

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to calculate the average cost of producing smoke shifters using a given function. It covers evaluating the cost for 12 units, determining the production level needed to reduce the cost to $11, and finding the horizontal asymptote of the cost function. The tutorial uses both algebraic and graphical methods to solve these problems, providing a comprehensive understanding of cost functions and asymptotic behavior.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the average cost to produce 12 smoke shifters?

$18.25

$17.00

$16.42

$15.50

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many smoke shifters must be produced to reduce the average cost to $11 each?

20

30

22

25

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the equation to find the number of smoke shifters needed for a specific average cost?

Subtract 125 from both sides

Multiply both sides by X

Add 6X to both sides

Divide both sides by 11

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does a horizontal asymptote represent in the context of this problem?

The cost of producing one additional unit

The maximum cost of production

The minimum cost of production

The average cost as production increases indefinitely

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which tool is used to find the horizontal asymptote graphically?

A ruler

A graphing calculator

A protractor

A spreadsheet

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the horizontal asymptote of the average cost function?

y = 5

y = 6

y = 7

y = 8

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you determine the horizontal asymptote by analyzing the function?

By dividing the constant terms

By finding the sum of coefficients

By subtracting the coefficients

By comparing the degrees of the numerator and denominator

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