Understanding Permutations and Counting Principles

Understanding Permutations and Counting Principles

Assessment

Interactive Video

Mathematics

7th - 12th Grade

Hard

Created by

Sophia Harris

FREE Resource

The video tutorial explains how to determine the number of ways to award first, second, and third prizes in a contest with 255 contestants. It covers two methods: the counting principle and permutations, emphasizing the importance of order in permutations. Both methods yield the same result, which is verified using a calculator.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the two methods mentioned for solving the problem of awarding prizes?

Counting principle and combination

Counting principle and permutation

Permutation and combination

Probability and statistics

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't a combination be used to solve the problem of awarding prizes?

Because the order of winners does not matter

Because the order of winners does matter

Because combinations require more contestants

Because combinations are only for identical items

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many ways can the first prize be awarded according to the counting principle?

254

256

255

253

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of ways to award the first, second, and third prizes using the counting principle?

16,386,830

16,386,800

16,386,810

16,386,820

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for calculating permutations?

n! / (n-r)!

r! / n!

n! / r!

(n-r)! / n!

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the permutation formula, what does 'r' represent?

The factorial of the chosen items

The total number of items

The number of items to choose

The factorial of the total items

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the permutation formula simplified in this problem?

By canceling out the numerator

By canceling out the denominator

By multiplying the numerator

By dividing the numerator

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