Understanding Limits of Functions of Two Variables

Understanding Limits of Functions of Two Variables

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

CCSS
HSF-IF.C.7D, HSF.LE.A.2, 8.F.B.4

Standards-aligned

Created by

Jackson Turner

FREE Resource

Standards-aligned

CCSS.HSF-IF.C.7D
,
CCSS.HSF.LE.A.2
,
CCSS.8.F.B.4
The video tutorial explains how to determine limits of functions of two variables, focusing on direct substitution when the function is continuous. It provides two examples: one with a polynomial function and another with a rational function, both evaluated at the point (2, 1). The tutorial emphasizes the importance of continuity in using direct substitution and briefly mentions the need to consider different paths when continuity is not present. The video concludes by offering additional examples for more complex scenarios.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the condition for the limit of a function of two variables to exist at a point?

The function must be zero at that point.

The function must be integrable at that point.

The limit must be the same from all paths approaching the point.

The function must be differentiable at that point.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is continuity important when finding limits using direct substitution?

It ensures the function is differentiable.

It allows the limit to be found without considering all paths.

It guarantees the function is bounded.

It makes the function periodic.

Tags

CCSS.HSF.LE.A.2

CCSS.8.F.B.4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first example, what is the limit of the function as x, y approaches 2, 1?

3

4

5

6

Tags

CCSS.HSF.LE.A.2

CCSS.8.F.B.4

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function used in the first example?

x^2 + 2y

2x + y^2

x + 2y^2

x + y^2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the second example, what is the limit of the rational function as x, y approaches 2, 1?

1/2

5/6

2/3

4/9

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can direct substitution be used in the second example?

The function is continuous at the point.

The function is periodic at the point.

The function is differentiable at the point.

The function is zero at the point.

Tags

CCSS.HSF-IF.C.7D

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What would be the issue if the function approached the point (0, 0) in the second example?

The function would have an indeterminate form.

The function would be differentiable.

The function would be continuous.

The function would be undefined.

Tags

CCSS.HSF-IF.C.7D

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