Differential Equations and Initial Conditions

Differential Equations and Initial Conditions

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

CCSS
8.EE.C.8B

Standards-aligned

Created by

Ethan Morris

FREE Resource

Standards-aligned

CCSS.8.EE.C.8B
The video tutorial explains how to solve a separable differential equation for u(t) given the equation du/dt = e^(6u + 9t) and the initial condition u(0) = 3. The process involves rewriting the equation in a separable form, integrating both sides, and using substitution to solve for u. The tutorial also demonstrates finding the particular solution using the initial condition and concludes with graphing the solution over a slope field.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial condition given in the problem?

u(1) = 0

u(1) = 3

u(0) = 3

u(0) = 0

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the differential equation rewritten to separate variables?

By adding a constant to both sides

By multiplying both sides by e^(-6u)

By dividing both sides by 9

By subtracting 9t from both sides

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is used for integrating the left side of the equation?

v = 6u

v = -6u

v = 9t

v = -9t

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the antiderivative of e^(9t) with respect to t?

1/6 e^(9t) + C

e^(9t) + C

9 e^(9t) + C

1/9 e^(9t) + C

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the next step after finding the general solution?

Differentiate the solution

Multiply by a constant

Find the particular solution using the initial condition

Graph the solution

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the constant 'c' determined in the particular solution?

By differentiating the general solution

By using the initial condition u(0) = 3

By integrating again

By setting t = 1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of 'c' in the particular solution?

e^(-9) + 2/3

e^(-18) + 2/3

e^(-9) + 1/3

e^(-18) + 1/3

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