Differential Equations and Initial Conditions

Differential Equations and Initial Conditions

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to solve a separable differential equation using separation of variables. It starts by introducing the problem and the initial conditions. The process involves separating variables, integrating both sides, and handling constants of integration. The tutorial then focuses on solving for X, considering the principal square root due to the initial condition. Finally, it demonstrates how to find the particular solution by substituting the initial conditions into the general solution.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial condition given in the problem?

x(0) = 9

x(0) = 18

x(0) = 7

x(0) = 0

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What method is used to solve the differential equation?

Laplace transform

Separation of variables

Integration by parts

Partial fraction decomposition

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After separating variables, what form does the equation take?

dx = 9xdt

xdx = 9dt

xdt = 9dx

dx = 9dt

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the integral of x with respect to x?

x + C

x^2/2 + C

x^2 + C

2x + C

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of integrating 9 with respect to t?

t + C

9t^2 + C

9 + C

9t + C

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the constant C related to C sub 1?

C = C sub 1

C = 2 * C sub 1

C = C sub 1 + 2

C = C sub 1 / 2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the negative square root not considered in the solution?

Because x(0) = 7 is positive

Because the initial condition is negative

Because x(0) = 0

Because the equation is not quadratic

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