Understanding Definite Integrals and Area Calculation

Understanding Definite Integrals and Area Calculation

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

CCSS
HSF.LE.B.5

Standards-aligned

Created by

Lucas Foster

FREE Resource

Standards-aligned

CCSS.HSF.LE.B.5
The video tutorial explains how to evaluate definite integrals by determining the area bounded by a function and the x-axis. It covers the calculation of integrals A(5) and A(9) by counting squares to find the area above and below the x-axis, considering positive and negative values respectively. The tutorial concludes with a summary of the results.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for A(x) in terms of an integral?

A(x) = integral of f(t) from x to 0

A(x) = integral of f(t) from 0 to x

A(x) = integral of f(t) from 5 to x

A(x) = integral of f(t) from x to 5

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do we evaluate definite integrals in this context?

By solving a differential equation

By finding the derivative of the function

By determining the area under the curve

By using a numerical approximation

Tags

CCSS.HSF.LE.B.5

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the area of the region above the x-axis from 0 to 5?

10 square units

8 square units

6 square units

5 square units

Tags

CCSS.HSF.LE.B.5

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many full squares are there in the region from 0 to 5?

8 full squares

5 full squares

6 full squares

7 full squares

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total area of the region from 0 to 9?

9 square units

8 square units

6 square units

5 square units

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the area of the region below the x-axis from 5 to 9?

4 square units

1 square unit

2 square units

3 square units

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do we treat the area below the x-axis when calculating the integral?

As a positive value

As a negative value

As twice the value

As zero

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