Understanding Concavity and Extrema

Understanding Concavity and Extrema

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial covers the analysis of a function f(x) = x * sqrt(x^2 + 4) over the interval [-4, 7]. It explains how to determine where the function is concave up or down by finding the second derivative. The tutorial also identifies points of inflection and calculates the absolute extrema by evaluating the function at endpoints. The process involves using the product and quotient rules for derivatives and simplifying expressions to find critical points.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary goal when analyzing the function f(x) = x * sqrt(x^2 + 4) on the interval [-4, 7]?

To find the roots of the function

To determine concavity, points of inflection, and absolute extrema

To find the asymptotes of the function

To calculate the integral of the function

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the function rewritten using rational exponents before finding the first derivative?

To apply the product rule more easily

To simplify the function for integration

To eliminate any fractions

To convert it into a polynomial

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which rule is applied to find the second derivative of the function?

Product Rule

Chain Rule

Quotient Rule

Power Rule

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the second derivative being zero or undefined?

It means the function is constant

It shows the function has no extrema

It helps find intervals of concavity and points of inflection

It indicates the function is linear

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

At which point does the function have a point of inflection?

(7, 0)

(-4, 0)

(0, 7)

(0, 0)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the absolute minimum of the function determined?

By evaluating the function at the endpoints

By finding where the first derivative is zero

By finding where the second derivative is zero

By evaluating the function at critical points

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the approximate value of the absolute minimum of the function?

-17.89

50.96

0

-8

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