Partial Fraction Decomposition Concepts

This video tutorial explains the process of finding the partial fraction decomposition of a rational expression. It begins with an introduction to the concept, followed by factoring the denominator and setting up the equation using variables A, B, and C. The tutorial then demonstrates how to clear fractions by multiplying by the least common denominator (LCD) and equating coefficients to solve for A, B, and C. Finally, it shows how to substitute these values back into the fractions to achieve the final decomposition.

What is the first step in finding the partial fraction decomposition of a rational expression?

• Factor the numerator completely

• Add a constant to both sides

• Multiply both sides by the LCD

• Factor the denominator completely

Tags

CCSS.HSA.APR.D.6

When dealing with repeated linear factors, how should the denominators of the fractions be set up?

• All fractions should have the same denominator

• Each fraction should have a unique linear factor

• Use increasing powers of the repeated factor

• Ignore the repeated factor

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CCSS.HSA.REI.A.2

What is the purpose of multiplying both sides of the equation by the LCD?

• To simplify the coefficients

• To factor the numerator

• To increase the degree of the numerator

• To eliminate the fractions

Which method is used in this example to find the values of A, B, and C?

• Substitution method

• Equating coefficients

• Graphical method

• Trial and error

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CCSS.8.EE.C.8C

What equation is formed after equating the coefficients of the terms?

• B + C = 0

• A + C = 1

• A + B = C

• A + B + C = 8

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CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the value of B after solving the system of equations?

• 2

• 1

• 3

• 4

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CCSS.6.EE.C.9

How is the value of A determined once B is known?

• By adding B to the equation

• By dividing B by 2

• By solving 4A + B = 0

• By subtracting B from the equation

Tags

CCSS.HSA.APR.D.6

What is the final form of the partial fraction decomposition?

• 2/X - 1/2X + 3/2(X+4)

• 2/X^2 - 1/2X + 3/2(X+4)

• 1/X - 2/X^2 + 3/2(X+4)

• 1/X^2 + 2/X + 3/2(X+4)

Tags

CCSS.HSA.APR.D.6

Why is the order of terms changed in the final decomposition?

• To avoid a negative first term

• To simplify the calculation

• To match the original expression

• To make the expression more complex

Tags

CCSS.HSA.APR.D.6

What is the value of C in the final decomposition?

• 1

• 1/2

• 2

• 3/2