Matrix Operations and Inverses

Matrix Operations and Inverses

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Lucas Foster

FREE Resource

This video tutorial explains how to solve a system of two linear equations with two unknowns using matrix equations. It covers setting up the equations in standard form, forming matrices A, X, and B, and solving the matrix equation A x X = B by finding the inverse of matrix A. The tutorial includes a detailed example and demonstrates how to verify the solution using a graphing calculator.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in setting up a system of linear equations for solving using matrices?

Arrange equations in standard form

Find the inverse of matrix A

Multiply matrices A and B

Graph the equations

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which matrix contains the coefficients of the variables in the system of equations?

Matrix C

Matrix X

Matrix B

Matrix A

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the order of multiplication important when solving the matrix equation A x X = B?

It changes the variables involved

It affects the size of the matrices

It determines the solution's accuracy

It ensures the identity matrix is formed

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of finding the inverse of matrix A in the matrix equation A x X = B?

To change the equation's form

To eliminate matrix A

To isolate matrix X

To simplify matrix B

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example, what is the standard form of the first equation after rearranging?

2Y = X + 1

X + 2Y = 1

2X + Y = 1

Y = 2X + 1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the elements of matrix B in the example provided?

3 and 5

1 and 2

2 and 3

1 and 1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the inverse of a 2x2 matrix calculated?

By adding identity matrix

By using the determinant and adjugate

By swapping rows and columns

By multiplying by a scalar

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