Finding Values with Perpendicular Bisectors

Finding Values with Perpendicular Bisectors

Assessment

Interactive Video

Mathematics

7th - 10th Grade

Hard

Created by

Emma Peterson

FREE Resource

This video tutorial explains how to solve for unknown values using the properties of perpendicular bisectors in triangles. It covers two examples: one for solving x and another for solving y, using the concept of segment congruence. A special case is also discussed where the perpendicular bisector passes through the opposite vertex, demonstrating that any point on the bisector is equidistant from the segment's endpoints. The video concludes with a verification of the solutions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary property of a perpendicular bisector in a triangle?

It is perpendicular to a side and bisects it.

It always passes through the centroid.

It is parallel to one side of the triangle.

It divides the triangle into two equal areas.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first example, what equation is set up to find the value of x?

2x - 6 = 90

x + 6 = 90

2x + 6 = 90

x - 6 = 90

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of x in the first example?

43

44

41

42

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the value of y determined in the first example?

By setting 3y - 1 equal to 23

By setting 3y - 1 equal to 46

By setting y - 1 equal to 23

By setting 3y + 1 equal to 23

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of y in the first example?

6

7

8

9

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the second example, what makes it a special case?

The bisector is parallel to the base.

The bisector is not perpendicular.

The bisector passes through the opposite vertex.

The bisector passes through the centroid.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation is used to find x in the second example?

2x + 1 = 45

2x - 1 = 45

x + 1 = 45

x - 1 = 45

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