Acetic Acid and Equilibrium Concepts

Acetic Acid and Equilibrium Concepts

Assessment

Interactive Video

Chemistry, Science

10th - 12th Grade

Hard

Created by

Sophia Harris

FREE Resource

The video tutorial explains the reaction between a weak acid, acetic acid, and a strong base, sodium hydroxide. It covers the calculation of moles for both reactants, the net ionic equation, and the use of an ICF table to analyze the reaction. The tutorial further explains how to calculate the concentrations of acetic acid and acetate anions, and how to determine the pH of the resulting solution using equilibrium concepts and the common ion effect. The final pH is calculated to be 4.74, indicating an acidic solution.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary goal of mixing acetic acid with sodium hydroxide in this experiment?

To calculate the freezing point of the solution

To measure the density of the solution

To find the pH of the resulting solution

To determine the boiling point of the solution

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many moles of acetic acid are present initially in the solution?

0.20 moles

0.30 moles

0.10 moles

0.40 moles

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the mole ratio of hydroxide ions to acetic acid in the net ionic equation?

2:1

1:2

1:1

3:1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After the reaction, what is the concentration of acetic acid in the solution?

0.25 M

0.50 M

0.75 M

1.00 M

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the common ion effect observed in this reaction?

The presence of a common ion has no effect on the solubility

The presence of a common ion decreases the solubility of the solute

The presence of a common ion increases the solubility of the solute

The presence of a common ion changes the color of the solution

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equilibrium expression for acetic acid in this reaction?

Ka = [H3O+][CH3COO-] / [CH3COOH]

Ka = [CH3COOH][OH-] / [H2O]

Ka = [CH3COOH][H2O] / [CH3COO-]

Ka = [H2O][CH3COO-] / [H3O+]

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What approximation is made to simplify the calculation of x in the equilibrium expression?

Assuming x is equal to 1

Assuming x is a very small number

Assuming x is equal to 0

Assuming x is a large number

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