Understanding Limits in Composite Functions

Understanding Limits in Composite Functions

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

CCSS
HSF.IF.A.2, HSF.IF.A.1

Standards-aligned

Created by

Mia Campbell

FREE Resource

Standards-aligned

CCSS.HSF.IF.A.2
,
CCSS.HSF.IF.A.1
The video tutorial explores the concept of limits involving two functions, g(x) and h(x). It begins by introducing the problem of finding the limit of g(h(x)) as x approaches 1. The tutorial then calculates the limit of h(x) and discusses the challenges in determining the limit of g(h(x)). By analyzing both left-handed and right-handed limits, it concludes that the limit of g(h(x)) is -2, despite the limit of g(x) at 2 not existing.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main objective of the problem discussed in the video?

To solve for x in the equation g(h(x)) = 0

To determine the limit of g(h(x)) as x approaches 1

To find the derivative of g(h(x))

To graph the functions g(x) and h(x)

Tags

CCSS.HSF.IF.A.2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

As x approaches 1, what value does h(x) approach from both sides?

0

1

2

Negative infinity

Tags

CCSS.HSF.IF.A.2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of g(2) according to the video?

1

2

-2

0

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why does the limit of g(x) at x=2 seem undefined?

Because h(x) is not defined at x=2

Because g(x) approaches different values from the left and right

Because g(x) is a constant function

Because g(x) is not continuous at x=2

Tags

CCSS.HSF.IF.A.1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the left-handed limit of g(h(x)) approach as x approaches 1?

0

-2

2

1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When approaching 1 from the left, what is h(x) approaching?

1 from below

2 from above

2 from below

1 from above

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the right-handed limit of g(h(x)) as x approaches 1?

1

2

0

-2

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