Volume of a Solid with Rectangular Cross-Sections

Volume of a Solid with Rectangular Cross-Sections

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to calculate the volume of a solid with a base defined by two intersecting graphs. The cross-sections of the solid are rectangles with a height equal to the x-coordinate. The tutorial walks through visualizing the graphs, determining the intersection points, and setting up a definite integral to find the volume. The process involves solving a quadratic equation, visualizing the parabola, and integrating the polynomial expression to find the volume of the solid.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the base of the solid defined by?

The region enclosed by y = -x^2 - 6x + 1 and y = 4

The region enclosed by y = x^2 - 6x + 1 and y = 4

The region enclosed by y = -x^2 + 6x - 1 and y = 4

The region enclosed by y = x^2 and y = 4

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in visualizing the graphs?

Calculating the area of the region

Drawing the graphs on a coordinate plane

Determining where the graphs intersect

Finding the vertex of the parabola

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

At which x-values do the graphs intersect?

x = 3 and x = 7

x = 2 and x = 4

x = 0 and x = 6

x = 1 and x = 5

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Where is the vertex of the parabola located?

x = 2

x = 3

x = 5

x = 4

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the y-coordinate of the vertex of the parabola?

y = 9

y = 8

y = 7

y = 6

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the height of the rectangular cross-sections?

The height is constant at 4

The height is equal to x

The height is equal to y

The height is equal to x^2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the width of the rectangles determined?

By the product of the two functions

By the sum of the two functions

By the difference between the upper and lower functions

By the average of the two functions

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