Understanding Tangent Lines and Implicit Differentiation

Understanding Tangent Lines and Implicit Differentiation

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

Created by

Emma Peterson

FREE Resource

The video tutorial explains how to find the coordinates of points on a closed curve where the tangent line is vertical. It begins by introducing the problem and then uses implicit differentiation to find the derivative of y with respect to x. The tutorial continues by solving for dy/dx and identifying the conditions under which the tangent is vertical. Finally, it calculates the specific x-values for y = -1, resulting in the coordinates of the points where the tangent is vertical.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main objective of the problem discussed in the video?

To find the area of the closed curve

To find the coordinates where the tangent is vertical

To calculate the length of the curve

To determine the slope of the tangent line

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which mathematical technique is used to find the derivative of y with respect to x?

Explicit differentiation

Implicit differentiation

Integration

Partial differentiation

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving for dy/dx using implicit differentiation?

Integrate both sides of the equation

Solve for y in terms of x

Differentiate both sides with respect to x

Differentiate both sides with respect to y

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for dy/dx after simplification?

x^2 + 2x + y^4 + 4y

4y^3 + 4

-(x + 1) / (2y^3 + 1)

2x + 2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to find when the denominator of dy/dx is zero?

To determine when the tangent is vertical

To calculate the maximum slope

To find when the curve is horizontal

To solve for x in terms of y

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What y-value makes the denominator of the derivative expression zero?

y = -1

y = 1

y = 0

y = 2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation do you solve to find the x-values when y = -1?

x^2 + 2x - 8 = 0

x^2 - 2x - 8 = 0

x^2 + 2x + 1 = 0

x^2 - 2x + 8 = 0

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