

Mean Value Theorem and Secant Lines
Interactive Video
•
Mathematics
•
9th - 12th Grade
•
Practice Problem
•
Hard
Standards-aligned
Emma Peterson
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is required for a function to apply the Mean Value Theorem?
The function must be differentiable over the closed interval.
The function must be differentiable over the closed interval and continuous over the open interval.
The function must be continuous over the open interval.
The function must be continuous over the closed interval and differentiable over the open interval.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the role of the secant line in the Mean Value Theorem?
It represents the average rate of change over the interval.
It is the tangent line at the midpoint of the interval.
It is the line connecting the endpoints of the function.
It is the line with the maximum slope in the interval.
Tags
CCSS.8.EE.B.5
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why does the Mean Value Theorem not apply to the interval [4, 6]?
The function is not continuous over the interval.
The function is not differentiable over the interval.
The endpoints of the interval are not included.
The slope of the secant line is not equal to 5.
Tags
CCSS.8.EE.B.5
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the slope of the secant line between points (4, f(4)) and (6, f(6))?
5
3
2
4
Tags
CCSS.8.EE.B.5
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the slope of the secant line for the interval [0, 2]?
-2
1
-1
0
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why can the Mean Value Theorem be applied to the interval [0, 2]?
The function is not continuous over the interval.
The endpoints of the interval are not included.
The slope of the secant line is equal to -1.
The function is not differentiable over the interval.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does the Mean Value Theorem guarantee for the interval [0, 2]?
There is a point where the derivative is maximum.
There is a point where the derivative is equal to the secant line slope.
There is a point where the derivative is 0.
There is a point where the derivative is minimum.
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