Understanding Relative Extrema in Calculus

Understanding Relative Extrema in Calculus

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial discusses Pamela's attempt to find the relative extremum of a function. She correctly identifies the critical point by setting the derivative to zero but mistakenly concludes it is an extremum without further testing. The instructor explains the need to check the derivative's behavior around the critical point to confirm if it is indeed an extremum, highlighting Pamela's error in her conclusion.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What was Pamela trying to find in the function h(x) = x^3 - 6x^2 + 12x?

The point of discontinuity

The absolute maximum

The relative extremum

The inflection point

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of h(x) = x^3 - 6x^2 + 12x?

3x^2 - 6x + 12

3x^2 - 12x + 12

3x^2 - 12x + 2

3x^2 - 4x + 4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

At which value of x did Pamela find a critical point?

x = 1

x = 3

x = 2

x = 0

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a critical point in the context of derivatives?

A point where the function has a maximum value

A point where the derivative is zero or undefined

A point where the function is undefined

A point where the second derivative is zero

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it incorrect to conclude a relative extremum just because the derivative is zero?

The derivative might not exist

The function might not be continuous

The function might have multiple critical points

The derivative might not change sign

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What must be verified to confirm a relative extremum at a critical point?

The second derivative's value

The function's domain

The derivative's sign change

The function's continuity

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What was the result of testing the derivative at x = 1 and x = 3?

The derivative was negative at both points

The derivative was zero at both points

The derivative was positive at both points

The derivative changed sign at both points

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