Understanding Graphs of Rational Functions

Understanding Graphs of Rational Functions

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explores the function f(x) = g(x)/(x^2 - x - 6), where g(x) is a polynomial. The instructor guides viewers through factoring the denominator to identify x-values that make it zero, leading to vertical asymptotes or removable discontinuities. The video evaluates multiple graph options to determine which one accurately represents the function, concluding that choice C is correct due to its vertical asymptote at x = -2 and removable discontinuity at x = 3.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of the problem introduced in the video?

Solving for x in the equation

Identifying the graph of y = f(x)

Finding the roots of g(x)

Determining the degree of g(x)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in analyzing the function f(x)?

Graphing the function

Factoring the denominator

Factoring the numerator

Finding the roots of g(x)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the critical x-values for the denominator of f(x)?

x = -3 and x = 2

x = 1 and x = -1

x = 3 and x = -2

x = 0 and x = 1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does a zero denominator indicate in the context of the graph?

A vertical asymptote or removable discontinuity

A horizontal asymptote

A local maximum or minimum

A point of inflection

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What condition must be met for a removable discontinuity to occur?

The numerator must not be zero at the same x-value

The denominator must be zero at a different x-value

The function must be continuous

The numerator must be zero at the same x-value

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which graph choice has a vertical asymptote at x = -2?

Choice B

Choice A

Choice D

Choice C

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is Choice A ruled out as a possible graph for f(x)?

It has no vertical asymptotes

It has a vertical asymptote at x = 3

It is defined at x = 3

It has a removable discontinuity at x = -2

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