Differential Equations and Initial Conditions

The video tutorial covers solving a separable differential equation. It begins with a problem statement, where the derivative of Y with respect to X equals two Y-squared, and a particular solution passes through the point (1, -1). The tutorial explains how to separate variables, integrate both sides, and solve for Y. It then uses the given point to find the constant C and concludes by finding Y when X equals three, resulting in Y = -1/5.

What is the initial condition given for the differential equation?

• Y passes through the point (3, 1)

• Y passes through the point (3, -1)

• Y passes through the point (1, -1)

• Y passes through the point (1, 1)

What is the first step in solving a separable differential equation?

• Integrate both sides immediately

• Add a constant to both sides

• Multiply both sides by a constant

• Separate the variables

Tags

CCSS.8.EE.C.8B

After separating variables, what operation is performed next?

• Integrate both sides

• Multiply both sides by a constant

• Differentiate both sides

• Add a constant to both sides

What is the result of integrating the left-hand side of the equation?

• 1/2 Y to the positive one power

• 1/2 Y to the negative one power

• -1/2 Y to the negative one power

• -1/2 Y to the positive one power

How is the constant of integration handled in this problem?

• It is ignored

• It is added to both sides

• It is subtracted from both sides

• It is only added to one side

Tags

CCSS.HSF.LE.B.5

What is the particular solution when the initial condition is applied?

• Y = 1/(2X - 1)

• Y = 1/(-2X + 2)

• Y = 1/(2X + 1)

• Y = 1/(-2X + 1)

What is the value of C when the initial condition is applied?

• C = 1

• C = 0

• C = 2

• C = -1

Tags

CCSS.HSF.IF.A.1

CCSS.8.F.A.1

What is the final value of Y when X equals 3?

• Y = 1/6

• Y = -1/6

• Y = 1/5

• Y = -1/5

What operation is performed to find Y from 1/Y?

• Square both sides

• Multiply both sides by a constant

• Add a constant to both sides

• Take the reciprocal of both sides

Tags

CCSS.6.EE.C.9

What is the expression for Y in terms of X and C?

• Y = 1/(-2X + C)

• Y = 1/(2X + C)

• Y = 1/(X + C)

• Y = 1/(-X + C)

Tags

CCSS.6.EE.C.9