Approximating Square Roots Using Local Linearization

Approximating Square Roots Using Local Linearization

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Practice Problem

Hard

CCSS
8.EE.A.2

Standards-aligned

Created by

Ethan Morris

FREE Resource

Standards-aligned

CCSS.8.EE.A.2
The video tutorial explains how to approximate the square root of 4.36 without a calculator by using the concept of local linearization. It begins by discussing the known value of the square root of 4 and introduces the function f(x) = sqrt(x). The tutorial then graphically represents the function and explains how to use the tangent line at x = 4 to approximate f(4.36). The derivative of the function is calculated to find the slope of the tangent line, which is then used to determine the approximate value of the square root. Finally, the approximation is validated using a calculator, showing that the method provides a close estimate.

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5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the square root of 4?

3

1

2

4

Tags

CCSS.8.EE.A.2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What function is used to approximate the square root of 4.36?

f(x) = 1/x

f(x) = x^3

f(x) = sqrt(x)

f(x) = x^2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of using a tangent line in this approximation?

To simplify the function

To find the exact value

To approximate values near a known point

To calculate the derivative

Tags

CCSS.8.EE.A.2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of f(x) = sqrt(x) at x = 4?

1/4

2

1/2

1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the approximate value of the square root of 4.36 using local linearization?

2.00

2.20

2.09

2.10

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