Understanding the Chain Rule

Understanding the Chain Rule

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial introduces the chain rule in calculus, starting with its abstract formula. It then demonstrates how to apply the chain rule in a concrete example, specifically finding the derivative of a composite function. The tutorial explains the process of defining functions f(x) and g(x), applying the power rule, and calculating the derivative of f' of g(x). The video concludes with a review of the steps involved in using the chain rule to find derivatives.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main purpose of the chain rule in calculus?

To find the derivative of a product of two functions

To find the derivative of a quotient of two functions

To find the integral of a function

To find the derivative of a composition of two functions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example provided, what is the function f(x) defined as?

x to the power of 3

x minus 3

The square root of x

3x squared minus x

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function g(x) in the example?

x squared

3x squared minus x

The square root of x

x plus 3

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the derivative of f(g(x)) expressed using the chain rule?

f'(x) * g'(x)

f'(g(x)) * g'(x)

f(x) * g(x)

f'(x) + g'(x)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of f(x) when f(x) is the square root of x?

x to the power of -1/2

1/2 * x to the power of 1/2

x to the power of 1/2

1/2 * x to the power of -1/2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of g(x) when g(x) is 3x squared minus x?

6x minus 1

3x squared

x minus 3

6x plus 1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final expression for the derivative of the composition f(g(x))?

1/2 * g(x) to the power of -1/2 * g'(x)

g(x) to the power of 1/2 * g'(x)

1/2 * g(x) to the power of 1/2 * g'(x)

g(x) to the power of -1/2 * g'(x)

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