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Maximizing Volume of Open Box

Maximizing Volume of Open Box

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Practice Problem

Hard

CCSS
8.EE.C.7B

Standards-aligned

Created by

Aiden Montgomery

FREE Resource

Standards-aligned

CCSS.8.EE.C.7B
The video tutorial addresses a classic problem of finding the volume of the largest open box that can be made from a 24-inch square piece of cardboard. The process involves cutting equal squares from the corners and folding up the sides. The tutorial explains how to set up the problem, calculate the volume as a function of x, and use derivatives to find the maximum volume. The solution is verified by solving the equation for critical points and confirming the maximum volume using the second derivative test.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial size of the cardboard used to create the open box?

20 inches square

24 inches square

30 inches square

18 inches square

Tags

CCSS.8.EE.C.7B

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How are the squares cut from the cardboard to form the open box?

By cutting unequal squares from the corners

By cutting rectangles from the sides

By cutting equal squares from the corners

By cutting circles from the corners

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for the base length of the box after cutting the squares?

24 - 2x

24 - 4x

24 - x

24 - 3x

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for the volume of the box in terms of x?

x(24 - x)^2

x(24 - 3x)^2

x(24 - 2x)^2

x(24 - 4x)^2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of the volume function used to find critical points?

10x^2 - 150x + 500

8x^2 - 96x + 384

14x^2 - 200x + 600

12x^2 - 192x + 576

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the critical points found for the volume function?

x = 3 and x = 9

x = 4 and x = 12

x = 6 and x = 14

x = 5 and x = 10

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is x = 12 not a suitable solution for maximizing the volume?

It results in a negative volume

It results in a zero volume

It results in a minimum volume

It results in a maximum volume

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