Carnot Engine Efficiency Concepts

Carnot Engine Efficiency Concepts

Assessment

Interactive Video

Physics, Science

9th - 12th Grade

Hard

Created by

Olivia Brooks

FREE Resource

This video tutorial explains how to solve problems related to the Carnot engine and its cycle. It covers calculating maximum efficiency using temperature values in Kelvin, solving problems involving heat energy absorption and release, and determining mechanical work performed by the engine. The video also discusses improving Carnot efficiency by adjusting reservoir temperatures and provides a detailed explanation of the Carnot cycle using a PV diagram.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula used to calculate the maximum efficiency of a Carnot engine?

1 - (Tc/Th)

Th - Tc

Tc - Th

Th/Tc

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If a Carnot engine absorbs 14,000 joules of heat energy, how much is discarded into the cold reservoir?

12,000 joules

6,000 joules

8,000 joules

10,000 joules

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the mechanical work performed by a Carnot engine calculated?

Product of Qh and Qc

Difference between Qh and Qc

Ratio of Qh to Qc

Sum of Qh and Qc

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the efficiency of a non-ideal heat engine if it performs 1,500 joules of work and absorbs 7,500 joules of heat?

20%

15%

25%

30%

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the maximum efficiency of a Carnot engine operating between 300 K and 600 K?

30%

60%

40%

50%

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can the efficiency of a Carnot engine be increased?

Increase the pressure of the system

Decrease the temperature of the hot reservoir

Increase the temperature of the cold reservoir

Decrease the temperature of the cold reservoir

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the efficiency of a Carnot engine if the cold reservoir temperature is decreased?

Efficiency becomes zero

Efficiency remains the same

Efficiency decreases

Efficiency increases

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