What is the primary reason the normal force is greater at point A compared to point B?

Normal Force and Centripetal Motion

Interactive Video
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Physics, Science
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9th - 12th Grade
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Hard

Mia Campbell
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10 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The box is heavier at point A.
The ground at point A is steeper.
The box needs to turn upward at point A.
The speed of the box is higher at point A.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the normal force at point A calculated?
By dividing the centripetal force by the weight force.
By adding the centripetal force and the weight force.
By subtracting the weight force from the centripetal force.
By multiplying the centripetal force with the weight force.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens to the normal force at point B if the box moves too fast?
It becomes negative, indicating loss of contact.
It increases, ensuring more stability.
It remains constant regardless of speed.
It doubles, providing extra support.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the condition for the maximum speed at which the box can maintain contact with the road at point B?
The normal force is equal to the centripetal force.
The normal force is zero.
The weight force is zero.
The centripetal force is zero.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the maximum speed at point B calculated?
By dividing the weight force by the radius.
By taking the square root of the product of radius and gravitational acceleration.
By multiplying the centripetal force by the radius.
By adding the weight force and centripetal force.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the minimum speed required for a roller coaster to prevent passengers from falling out when upside down?
The speed must be double the square root of rg.
The speed must be greater than the square root of rg.
The speed must be equal to the square root of rg.
The speed must be less than the square root of rg.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the roller coaster problem, what direction does the normal force point when the coaster is upside down?
Away from the center of the circle
Towards the center of the circle
Negative y direction
Positive y direction
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