Understanding Tangent Lines and Derivatives

Understanding Tangent Lines and Derivatives

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Easy

Created by

Amelia Wright

Used 1+ times

FREE Resource

The video tutorial explains how to find the equation of a horizontal tangent line to a curve given by an equation. It starts by introducing the problem and the derivative of y with respect to x. The tutorial then visualizes the curve and identifies potential horizontal tangent lines. It explains that the derivative is zero when the numerator of the derivative expression is zero. By substituting x = -3 into the original equation, the corresponding y values are found. The tutorial concludes by identifying the horizontal tangent line above the x-axis as y = 2.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main goal of the problem discussed in the video?

To find the equation of a vertical line tangent to the curve.

To calculate the area under the curve.

To determine the slope of the curve at a given point.

To write the equation of a horizontal line tangent to the curve above the x-axis.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What mathematical technique is suggested to find the derivative of y with respect to x?

Partial differentiation

Numerical integration

Implicit differentiation

Explicit differentiation

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does a horizontal tangent line indicate about the derivative at that point?

The derivative is undefined.

The derivative is zero.

The derivative is negative.

The derivative is positive.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the context of the video, what is the significance of the numerator of the derivative being zero?

It shows the curve is decreasing.

It signifies a horizontal tangent line.

It means the curve is increasing.

It indicates a vertical tangent line.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What value of x makes the numerator of the derivative zero?

x = 3

x = 2

x = -3

x = 0

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation is used to find the corresponding y-value when x is -3?

2x + y^3 = 7

x^3 + y^2 = 7

x^2 + y^4 + 6x = 7

y^2 + 3x = 7

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the possible y-values when x is -3?

y = 2 or y = -2

y = 1 or y = -1

y = 3 or y = -3

y = 4 or y = -4

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