Understanding Geometric Random Variables

The video tutorial explains Jeremiah's shooting strategy, focusing on his 25% success rate for three-point shots. It introduces the concept of geometric random variables, defining the number of trials needed for a success. The tutorial calculates the probability of Jeremiah making his first successful shot on his third attempt, detailing the steps involved in the calculation. The probability is determined by considering the chances of missing the first two shots and making the third, resulting in a 14% probability.

What percentage of three-point shots does Jeremiah make?

• 25%

• 75%

• 10%

• 50%

What type of random variable is used to model Jeremiah's shooting?

• Normal

• Binomial

• Poisson

• Geometric

What does the random variable M represent in this context?

• The total number of shots taken

• The number of successful shots

• The number of shots until the first success

• The number of missed shots

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CCSS.HSS.CP.A.5

Why are the results of each shot considered independent?

• Because the outcome of one shot does not affect another

• Because the shots are taken on different days

• Because Jeremiah uses different techniques

• Because the probability of success changes

Tags

CCSS.HSF.BF.A.2

What is the probability that Jeremiah's first successful shot occurs on his third attempt?

• 1/64

• 1/4

• 3/4

• 9/64

Tags

CCSS.HSF.BF.A.2

What must happen for Jeremiah to succeed on his third attempt?

• He must miss all three shots

• He must make all three shots

• He must miss the first two shots and make the third

• He must make the first two shots and miss the third

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CCSS.7.SP.C.5

How is the probability of missing a shot calculated?

• By dividing the probability of making a shot by 2

• By subtracting the probability of making a shot from 1

• By adding the probability of making a shot to 1

• By multiplying the probability of making a shot by 2

What is the decimal equivalent of the probability that Jeremiah succeeds on his third attempt?

• 0.09

• 0.14

• 0.25

• 0.36

Tags

CCSS.HSF.BF.A.2

What is the approximate percentage chance that Jeremiah's first successful shot occurs on his third attempt?

• 14%

• 25%

• 36%

• 9%

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CCSS.HSA.SSE.B.4

What does the final probability result indicate about Jeremiah's shooting?

• He will definitely succeed on the third attempt

• He is unlikely to succeed on any attempt

• He has a moderate chance of succeeding on the third attempt

• He is very likely to succeed on the first attempt

Tags

CCSS.HSA.SSE.B.4