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Taylor Series and Cosine Functions

Taylor Series and Cosine Functions

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Practice Problem

Hard

CCSS
HSF.IF.A.1

Standards-aligned

Created by

Mia Campbell

FREE Resource

Standards-aligned

CCSS.HSF.IF.A.1
The video tutorial explains how to find the first four non-zero terms of the Taylor series for cosine of x about x equals 0. It then uses this series, along with the series for sine of x squared, to derive the Taylor series for a function f(x) = sine(x^2) + cosine(x). The process involves calculating derivatives, identifying non-zero terms, and simplifying the series to achieve the final result.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the task in part b of the problem?

Find the derivative of cosine of x.

Find the integral of sine of x.

Find the Taylor series for sine of x.

Find the first four non-zero terms of the Taylor series for cosine of x about x equals 0.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the first derivative of cosine of x at x equals 0?

-1

0

2

1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which term is not included in the first four non-zero terms of the Taylor series for cosine of x?

1

-x^2/2!

x^4/4!

x^3/3!

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of approximating cosine of x with the first four non-zero terms?

To find the integral of cosine of x.

To approximate cosine of x using a polynomial.

To simplify the calculation of cosine of x.

To find the exact value of cosine of x.

Tags

CCSS.HSF.IF.A.1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function f(x) defined as in the second part of the problem?

cosine of x squared

sine of x squared plus cosine of x

sine of x

cosine of x

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the lowest degree term in the Taylor series for f(x) = sine of x squared + cosine of x?

x

x^3

x^2

1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the x^6 term in the Taylor series for f(x) simplified?

By dividing x^6/3! by x^6/6!

By adding x^6/3! and x^6/6!

By subtracting x^6/3! from x^6/6!

By multiplying x^6/3! by x^6/6!

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