Understanding Sn2 Reactions

Understanding Sn2 Reactions

Assessment

Interactive Video

Chemistry, Science

10th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains Sn2 reactions, a type of nucleophilic substitution in organic chemistry. It covers the interaction between bromomethane and hydroxide, detailing the one-step reaction mechanism. The tutorial highlights the transition state and rate-determining step, emphasizing the involvement of both reactants. The video also touches on the concept of chirality in Sn2 reactions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the '2' in Sn2 reactions signify?

The rate-determining step involves two reactants.

The reaction produces two products.

The reaction involves two steps.

The reaction requires two catalysts.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In an Sn2 reaction, what role does the nucleophile play?

It accepts an electron.

It donates an electron.

It forms a double bond.

It donates a proton.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is considered a leaving group in Sn2 reactions?

Hydroxide

Hydrogen

Carbon

Bromine

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the nucleophile during the Sn2 reaction mechanism?

It is expelled from the reaction.

It becomes positively charged.

It forms a temporary bond with the substrate.

It remains unchanged.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge on the bromine atom after it leaves in an Sn2 reaction?

Double negative

Neutral

Negative

Positive

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following best describes a nucleophile?

A molecule that donates protons

A molecule that donates electrons

A molecule that accepts electrons

A molecule that forms covalent bonds

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of the substrate in an Sn2 reaction?

It donates electrons.

It is replaced by the nucleophile.

It acts as a catalyst.

It forms a double bond.

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