Understanding Nucleophilicity

Understanding Nucleophilicity

Assessment

Interactive Video

Chemistry, Science

10th - 12th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains nucleophilicity, defining it as the ability of an atom, ion, or molecule to donate electrons and form bonds with nuclei. It identifies good nucleophiles, such as negative ions and anions, and discusses halides like fluoride, chloride, bromide, and iodide. The hydroxide anion is also highlighted as a nucleophile. The tutorial differentiates between protic and aprotic solvents, explaining their impact on nucleophilicity. In protic solvents, iodide is the best nucleophile, while in aprotic solvents, fluoride is more effective due to its basicity.

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is nucleophilicity primarily concerned with?

The ability to donate protons

The ability to donate electrons

The ability to accept electrons

The ability to form hydrogen bonds

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is a characteristic of a good nucleophile?

Being a large atom

Having extra electrons to donate

Being a neutral molecule

Having a positive charge

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ion is an example of a good nucleophile?

Calcium ion

Fluoride ion

Sodium ion

Hydrogen ion

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What defines a protic solvent?

It can donate protons

It has no hydrogen atoms

It is non-polar

It is a gas at room temperature

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is an example of an aprotic solvent?

Ammonia

Diethyl ether

Methanol

Water

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a protic solvent, which nucleophile is most likely to be hindered by hydrogen bonding?

Iodide

Chloride

Fluoride

Bromide

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the size of iodide affect its nucleophilicity in protic solvents?

It makes it more polarizable

It makes it a poor nucleophile

It makes it less polarizable

It prevents it from forming hydrogen bonds

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