

Jason's Journey: Distance and Time Calculations
Interactive Video
•
Mathematics
•
6th - 8th Grade
•
Practice Problem
•
Hard
+3
Standards-aligned
Lucas Foster
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What was Jason's average speed while biking to the train station?
15 miles per hour
10 miles per hour
20 miles per hour
5 miles per hour
Tags
CCSS.4.MD.A.2
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the total distance Jason traveled during his trip?
20 miles
25 miles
30 miles
35 miles
Tags
CCSS.6.EE.B.7
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the time taken by train calculated in terms of distance and speed?
Time = Distance x Speed
Time = Distance / Speed
Time = Speed / Distance
Time = Speed x Distance
Tags
CCSS.6.EE.B.7
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the speed of the train during Jason's journey?
30 miles per hour
40 miles per hour
50 miles per hour
60 miles per hour
Tags
CCSS.HSA.CED.A.3
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What equation represents the total time taken for Jason's trip?
Time by train = Time by bike
Time by train + Time by bike = 1 hour
Time by train - Time by bike = 1 hour
Time by train + Time by bike = 2 hours
Tags
CCSS.7.EE.B.4A
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in solving for the distance traveled by train?
Divide the total distance by 2
Multiply the train distance by 2
Subtract the bike distance from the total distance
Add the distances of train and bike
Tags
CCSS.4.MD.A.2
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the distance traveled by train according to the solution?
15 miles
25 miles
30 miles
20 miles
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