Partial Fraction Decomposition Concepts

Partial Fraction Decomposition Concepts

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Practice Problem

Hard

CCSS
6.EE.B.7

Standards-aligned

Created by

Jackson Turner

FREE Resource

Standards-aligned

CCSS.6.EE.B.7
This video tutorial covers partial fraction decomposition with repeated factors in the denominator. It begins by explaining the problem setup and why certain decomposition methods are incorrect. The correct method is introduced, followed by solving for coefficients A, B, and C. The tutorial concludes with a generalization of the method for higher degree terms.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a unique challenge when dealing with repeated factors in partial fraction decomposition?

They require additional variables.

They can be ignored.

They simplify the problem.

They require the same approach as non-repeated factors.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't you simply add terms with the same denominator in partial fraction decomposition?

It would eliminate the need for decomposition.

It would increase the degree of the numerator.

It would make the equation unsolvable.

It would result in a single variable.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the correct form for decomposing a fraction with a repeated factor x-2 squared?

A/(x-1) + B/(x-2)^2

A/(x-1) + B/(x-2) + C/(x-2)^2

A/(x-1) + B/(x-2) + C/(x-2)

A/(x-1) + B/(x-2)^2 + C/(x-2)^3

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What value of x is chosen to solve for A in the given problem?

x = 1

x = 0

x = 3

x = 2

Tags

CCSS.6.EE.B.7

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of A after solving the equation?

A = 1

A = 2

A = 4

A = 3

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which value of x is used to solve for C?

x = 0

x = 3

x = 1

x = 2

Tags

CCSS.6.EE.B.7

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of C after solving the equation?

C = 1

C = 2

C = 4

C = 3

Tags

CCSS.6.EE.B.7

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