Hyperbola Graphing Quiz

Hyperbola Graphing Quiz

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

This video tutorial covers the process of graphing a hyperbola, starting with identifying the type of conic section and recognizing its shifted form. It explains how to calculate the slopes of the asymptotes and plot them, followed by graphing the hyperbola itself and determining its orientation. The tutorial emphasizes understanding the underlying concepts rather than just memorizing formulas.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in graphing a hyperbola?

Plotting points on the graph

Identifying the type of conic section

Drawing the asymptotes

Finding the center

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you recognize a hyperbola from its equation?

By the presence of a multiplication sign between terms

By the presence of a plus sign between terms

By the presence of a minus sign between terms

By the presence of a division sign between terms

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the center of the hyperbola given by the equation (x-1)^2/16 - (y+1)^2/4 = 1?

(0, 0)

(1, -1)

(-1, 1)

(1, 1)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the asymptotes in a hyperbola?

They are the maximum and minimum points of the hyperbola

They are the lines the hyperbola approaches but never touches

They are the axes of symmetry

They determine the center of the hyperbola

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you determine the slopes of the asymptotes for the hyperbola centered at (1, -1)?

By solving for x

By using the constant term

By solving for y

By using the coefficients of the squared terms

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the orientation of the hyperbola if the positive square root is always slightly below the asymptote?

Diagonal

Horizontal

Circular

Vertical

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens when y is equal to -1 in the equation (x-1)^2/16 - (y+1)^2/4 = 1?

The x-term becomes zero

The y-term becomes zero

The equation becomes undefined

The equation becomes a circle

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