Double angle of tangent given a triangle

Double angle of tangent given a triangle

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

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The video tutorial covers solving a trigonometric problem where a trigonometric function and a constraint are given instead of an angle. The instructor explains how to draw a triangle within specific constraints, apply the Pythagorean theorem, and calculate the tangent of 2 beta. Key points include understanding the secant function, correctly applying positive and negative values, and simplifying expressions.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the secant function a ratio of?

Opposite over Hypotenuse

Hypotenuse over Adjacent

Adjacent over Opposite

Hypotenuse over Opposite

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to consider the quadrant when solving trigonometric problems?

To simplify the calculations

To identify the correct trigonometric function

To determine the size of the angle

To ensure the signs of the components are correct

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the simplified form of sqrt(8)?

4 radical 2

2.8284271

2 radical 2

3 radical 2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for the tangent of double angles?

2 * tangent of beta / (1 + tangent of beta squared)

tangent of beta squared / (1 - 2 * tangent of beta)

tangent of beta / (1 - tangent of beta squared)

2 * tangent of beta / (1 - tangent of beta squared)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final simplified expression for tangent of 2 beta in this problem?

-4 sqrt 2 / 7

2 sqrt 2 / 7

4 sqrt 2 / 7

-2 sqrt 2 / 7