How to identify vertical and horizontal asymptotes with holes

How to identify vertical and horizontal asymptotes with holes

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

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The video tutorial explains how to find vertical and horizontal asymptotes by setting the denominator equal to zero and using the degree test. It emphasizes the importance of simplifying expressions to identify discontinuities and holes. The process of factoring is used to determine which discontinuities are holes and which are asymptotes. The tutorial concludes with a method to find horizontal asymptotes by comparing the degrees of the numerator and denominator.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to set the denominator equal to zero when finding vertical asymptotes?

To determine the y-intercepts

To find the x-intercepts

To calculate the slope of the line

To identify potential discontinuities

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of simplifying expressions when identifying discontinuities?

To determine the degree of the polynomial

To find the horizontal asymptotes

To check if any discontinuities are removable holes

To ensure all discontinuities are asymptotes

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example provided, why is x - 2 considered a hole?

Because it is a horizontal asymptote

Because it is a non-removable discontinuity

Because it is a vertical asymptote

Because it is a removable discontinuity

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you determine the horizontal asymptote using the degree test?

By setting the denominator equal to zero

By comparing the coefficients of the highest degree terms

By comparing the degrees of the numerator and denominator

By setting the numerator equal to zero

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the horizontal asymptote when the degree of the numerator is less than the degree of the denominator?

Y equals infinity

Y equals 0

Y equals the leading coefficient

Y equals 1