
Teacher explains completing the square to solve an equation
Interactive Video
•
Mathematics
•
11th Grade - University
•
Practice Problem
•
Hard
Wayground Content
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7 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the initial method discussed for solving quadratic equations before completing the square?
Using the quadratic formula
Using synthetic division
Graphing the equation
Factoring the equation
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in creating a perfect square trinomial?
Add a constant to both sides
Multiply the equation by a constant
Divide the equation by a constant
Isolate the variable terms
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you determine the value to add to both sides to create a perfect square trinomial?
Add the linear coefficient to the constant term
Divide the linear coefficient by 2 and square it
Multiply the linear coefficient by 2 and square it
Subtract the linear coefficient from the constant term
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why can't the Zero Product Property be applied directly after creating a perfect square trinomial?
The equation does not equal zero
The equation is not factorable
The equation has no real solutions
The equation is not quadratic
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the next step after rewriting the equation as a binomial squared?
Apply the quadratic formula
Use inverse operations to solve for the variable
Graph the equation
Check for extraneous solutions
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
When solving the binomial squared equation, what must be considered when introducing the square root?
Only the positive root is valid
The square root can be ignored
Both positive and negative roots must be considered
The square root must be multiplied by the constant term
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What should be checked after finding the solution to the binomial squared equation?
If the solution is less than zero
If the solution is a whole number
If the solution is positive
If the solution satisfies the original equation
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