Evaluate the six trig functions by when given one value and constraint

The video tutorial addresses a problem involving the tangent of theta, initially causing confusion due to incorrect notation. The instructor explains the need to consider two possible triangles due to negative values and demonstrates how to represent them on Cartesian coordinates. The correct triangle is chosen based on the constraint that sine is less than zero, which limits the possible quadrants. The instructor then calculates the sine, cosine, and tangent of theta, along with their reciprocal functions, providing a comprehensive understanding of the problem.

What is the initial value of tangent of Theta discussed in the video?

• 4 / 3

• 4π / 3

• -4 / 3

• -4π / 3

Why are there two possible triangles when representing the tangent value?

• Because tangent can be positive or negative

• Because triangles can be drawn in different quadrants

• Because the negative sign can be on either the numerator or the denominator

• Because the unit circle has two halves

In which quadrants is the sine of Theta less than zero?

• First and Second

• First and Fourth

• Second and Third

• Third and Fourth

What is the hypotenuse of the triangle used to find the trigonometric functions?

• 6

• 5

• 4

• 3

What is the value of the cosine of Theta?

• 3 / 5

• -4 / 5

• -3 / 5

• 4 / 5