Using Semi-Log Graphs to Estimate Parameters for Exponential Equations

Using Semi-Log Graphs to Estimate Parameters for Exponential Equations

Assessment

Interactive Video

Mathematics

University

Hard

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The video tutorial explains how to use log graphs to estimate parameters in equations of the form y = kb^x. It covers the process of taking logs of both sides, rearranging equations, and understanding semilog graphs. An example is provided to demonstrate how to calculate the values of k and b using semilog graphs. The tutorial concludes with a summary of the key points and advice for assessments.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary difference in the variable x between the current and previous lecture presentations?

x is a base in the current lecture.

x is a constant in the current lecture.

x is a power in the current lecture.

x is a coefficient in the current lecture.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When transforming the equation using logarithms, what does the term log b represent in the linear equation?

The constant term

The y-intercept

The x-intercept

The slope

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the context of a semilog graph, what does the y-intercept represent?

log b

log k

log x

log y

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you determine the value of b from the gradient of a semilog graph?

By multiplying the gradient by 10

By taking the natural log of the gradient

By raising 10 to the power of the gradient

By dividing the gradient by 10

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of k if the y-intercept of the semilog graph is 0.69897?

3

5

10

7

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of graph results from taking the log of the y-values in an exponential equation?

A parabolic graph

A log-log graph

A semilog graph

A linear graph

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What should you remember about the gradient and y-intercept when using semilog graphs?

The gradient is log k and the y-intercept is log b

The gradient is log b and the y-intercept is log k

Both are equal to log y

They are not related to logarithms

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