Use u substitution with trigonometric functions

Use u substitution with trigonometric functions

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

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The video tutorial explains how to solve an integral involving the tangent function by using U substitution. It begins by identifying the derivative of tangent as secant squared, then defines U as tangent of X and DU as secant squared of X DX. The integral is rewritten in terms of U and DU, and the solution is found by integrating U squared DU, resulting in U cubed divided by three plus C. The integral is then plugged back in to complete the solution.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of the tangent function?

Secant squared

Sine squared

Cosecant squared

Cosine squared

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the substitution process, what is U set to?

Sine of X

Cosine of X

Tangent of X

Secant of X

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for du in terms of X?

Secant squared of X times DX

Cosine squared of X times DX

Tangent squared of X times DX

Sine squared of X times DX

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the integral of U squared with respect to U?

U squared divided by 2 plus C

U cubed divided by 3 plus C

U to the fourth divided by 4 plus C

U to the fifth divided by 5 plus C

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is added to the result of the integration to complete the solution?

A derivative term

A variable of integration

A constant of integration

A substitution term