Use u substitution with trigonometric functions

The video tutorial explains how to solve an integral involving the tangent function by using U substitution. It begins by identifying the derivative of tangent as secant squared, then defines U as tangent of X and DU as secant squared of X DX. The integral is rewritten in terms of U and DU, and the solution is found by integrating U squared DU, resulting in U cubed divided by three plus C. The integral is then plugged back in to complete the solution.

Discuss the importance of understanding the relationship between U and its derivative in integration.

How do you plug the integral back into the original function?