Crystal Field Stabilization Energy (CFSE) 3: Low-Spin Example

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Science, Chemistry, Physics
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Hard
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7 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in calculating the crystal field stabilization energy for a coordination complex?
Determine the geometry of the complex
Measure the bond angles
Calculate the metal's oxidation state
Identify the ligands involved
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How many d-electrons are present in molybdenum 2+?
8
6
4
2
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What determines whether a complex is low spin or high spin?
The overall charge of the complex
The number of d-electrons and whether it is a first-row transition metal
The type of metal
The number of ligands
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In a low spin complex, how are the d-electrons filled in the crystal field diagram?
Electrons fill orbitals randomly
Electrons fill the higher energy orbitals first
Electrons fill the lower energy orbitals first
Electrons are evenly distributed across all orbitals
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the role of the degenerate energy in the crystal field diagram?
It affects the geometry of the complex
It is the reference point for measuring energy differences
It determines the overall charge of the complex
It indicates the number of unpaired electrons
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the significance of pairing energy in low spin complexes?
It increases the number of unpaired electrons
It decreases the overall energy of the complex
It represents the energy cost of pairing electrons in the same orbital
It has no effect on the stabilization energy
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the crystal field stabilization energy calculated for a low spin complex?
By adding the energies of all filled orbitals
By subtracting the pairing energy from the stabilization energy of the t2g orbitals
By multiplying the number of electrons by the energy difference between orbitals
By considering only the e_g orbitals
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