Crystal Field Stabilization Energy (CFSE) 3: Low-Spin Example

Crystal Field Stabilization Energy (CFSE) 3: Low-Spin Example

Assessment

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Science, Chemistry, Physics

University

Hard

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The video tutorial explains how to calculate the crystal field stabilization energy for a coordination complex, specifically hexa amine molybdenum 2. It covers the steps to determine the metal's charge and oxidation state, calculate the number of D electrons, and decide whether the complex is low or high spin. The tutorial also demonstrates setting up a crystal field diagram and calculating the stabilization energy, including considerations for pairing energy.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in calculating the crystal field stabilization energy for a coordination complex?

Determine the geometry of the complex

Measure the bond angles

Calculate the metal's oxidation state

Identify the ligands involved

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many d-electrons are present in molybdenum 2+?

8

6

4

2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What determines whether a complex is low spin or high spin?

The overall charge of the complex

The number of d-electrons and whether it is a first-row transition metal

The type of metal

The number of ligands

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a low spin complex, how are the d-electrons filled in the crystal field diagram?

Electrons fill orbitals randomly

Electrons fill the higher energy orbitals first

Electrons fill the lower energy orbitals first

Electrons are evenly distributed across all orbitals

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of the degenerate energy in the crystal field diagram?

It affects the geometry of the complex

It is the reference point for measuring energy differences

It determines the overall charge of the complex

It indicates the number of unpaired electrons

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of pairing energy in low spin complexes?

It increases the number of unpaired electrons

It decreases the overall energy of the complex

It represents the energy cost of pairing electrons in the same orbital

It has no effect on the stabilization energy

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the crystal field stabilization energy calculated for a low spin complex?

By adding the energies of all filled orbitals

By subtracting the pairing energy from the stabilization energy of the t2g orbitals

By multiplying the number of electrons by the energy difference between orbitals

By considering only the e_g orbitals