Complete Java SE 8 Developer Bootcamp - “this”-Part 1

Complete Java SE 8 Developer Bootcamp - “this”-Part 1

Assessment

Interactive Video

Information Technology (IT), Architecture

University

Hard

Created by

Quizizz Content

FREE Resource

The video tutorial explains the 'this' keyword in Java, focusing on its use in accessing object variables directly. It covers method frames, variable resolution, and the importance of using 'this' to avoid naming collisions. The tutorial also demonstrates refactoring techniques in Eclipse to handle variable naming issues effectively.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary purpose of the 'this' keyword in Java?

To create a new object

To refer to the current object instance

To declare a new variable

To import a package

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the customize method, what happens to the parameters passed to it?

They are ignored

They are added as local variables in the frame

They are stored in a global variable

They replace existing object variables

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the 'this' keyword help in resolving variables?

It directly accesses the object on the heap

It duplicates the variable

It deletes the variable

It creates a new variable

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens if a variable is not found in the frame during method execution?

The program crashes

A new variable is created

The method returns null

The object on the heap is checked

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why might Java developers prefer using 'this' in their code?

To reduce memory usage

To avoid variable name collisions

To increase execution speed

To simplify syntax

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the effect of using 'this' in front of a method call?

It skips the frame and accesses the object directly

It duplicates the method

It creates a new method

It deletes the method

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What issue arises when parameter names are the same as object variable names?

The object is deleted

The method becomes static

The assignment to the variable has no effect

The program runs faster