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Integrated Rate Laws (2/3): Second Order Calculation

Integrated Rate Laws (2/3): Second Order Calculation

Assessment

Interactive Video

Science, Mathematics

University

Practice Problem

Easy

Created by

Wayground Content

Used 1+ times

FREE Resource

The video revisits a problem from a previous video, where the rate constant was determined assuming a first order reaction. It then calculates the rate constant assuming a second order reaction using the integrated rate law. The video explains the derivation of the units for a second order rate constant and concludes by highlighting the differences in rate constants due to different reaction orders. The next video will explore determining the true reaction order using additional data.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What was the initial concentration of reactant A in the problem discussed?

0.8 molar

0.6 molar

0.4 molar

0.2 molar

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which equation is used to calculate the rate constant for a second-order reaction?

ln[A]t = ln[A]0 - kt

Rate = k[A]

Rate = k[A]^2

1/[A]t = 1/[A]0 + kt

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the calculated second-order rate constant for the reaction?

0.0244 inverse molar inverse seconds

0.0741 inverse molar inverse seconds

0.0244 per second

0.0741 per second

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How are the units for a second-order rate constant derived?

By multiplying rate by concentration squared

By dividing rate by concentration squared

By multiplying concentration by time

By dividing rate by concentration

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the units for a second-order rate constant?

Inverse molar per second

Molar squared per second

Molar per second

Inverse molar inverse seconds

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