Practice Problem: Empirical and Molecular Formulas
Interactive Video
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Physics, Science, Chemistry
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11th Grade - University
•
Practice Problem
•
Hard
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7 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in determining the molecular formula of nicotine?
Find the empirical formula first.
Assume a random mass for calculations.
Convert mass percentages to grams.
Calculate the molar mass directly.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you convert the mass of carbon in nicotine to moles?
Multiply by 1 mole over 12.01 grams.
Multiply by 1 mole over 16.00 grams.
Multiply by 1 mole over 1.008 grams.
Multiply by 1 mole over 14.01 grams.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it important to convert mass percentages to moles in this calculation?
Moles are the same as percentages.
Moles are easier to calculate than grams.
Moles allow for the determination of atomic ratios.
Moles provide a direct measure of mass.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the empirical formula of nicotine based on the given calculations?
C6H8N
C4H6N
C5H7N
C10H14N2
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the molar mass of nicotine as calculated in the tutorial?
81.13 grams per mole
162.3 grams per mole
100 grams per mole
200 grams per mole
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the molecular formula of nicotine determined from the empirical formula?
By adding one more nitrogen atom.
By halving the empirical formula.
By doubling the empirical formula.
By tripling the empirical formula.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final molecular formula of nicotine?
C10H14N2
C5H7N
C6H8N
C4H6N
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