What is the pattern observed in perfect square trinomials?
Transforming Quadratic Equations Using Completing the Square

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Mathematics, Social Studies
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1st - 6th Grade
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Hard
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7 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The constant term is the square of half the linear term.
The linear term is double the constant term.
The quadratic term is the square of the constant term.
The constant term is half the quadratic term.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it important to maintain equality when transforming equations?
To make the equation more complex.
To ensure the equation remains balanced.
To simplify the equation.
To change the equation's solution.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in transforming a quadratic equation using completing the square?
Add a constant to both sides.
Divide both sides by the quadratic coefficient.
Isolate the terms with X.
Multiply both sides by a constant.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why do we factor out the coefficient of the quadratic term?
To simplify the equation.
To make the quadratic term a perfect square.
To change the equation's solution.
To eliminate the quadratic term.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What must be done after adding a term inside the parentheses to maintain equality?
Multiply the term by the quadratic coefficient.
Divide the term by the linear coefficient.
Subtract the same term from both sides.
Add the equivalent value outside the parentheses.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How can you verify that the transformation of a quadratic equation is correct?
By checking the coefficients of both equations.
By simplifying both equations to the same form.
By solving both equations and comparing solutions.
By graphing both equations and checking for equivalence.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does it mean if the graphs of the original and transformed equations look the same?
The transformation changed the equation's values.
The equations are not equivalent.
The transformation was done correctly.
The equations have different solutions.
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