Practice Problem: Graham's Law of Effusion

The video tutorial explains how to use Graham's law of effusion to identify an unknown gas. Methane effuses at 1.414 times the rate of the unknown gas. By using the formula relating effusion rates and molar masses, the tutorial guides viewers through the calculation process. The molar mass of methane is known, and by solving the equation, the molar mass of the unknown gas is found to be approximately 32 grams per mole, suggesting it is likely oxygen gas.

What value do you get for the molar mass of gas B after applying Graham's law?

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Based on the calculated molar mass, which common gas could gas B likely be?

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